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参见英文答案 > Rest Template custom exception handling 2个
是否可以使用Spring RestTemplate而不使用Exceptions来处理状态为500的http响应?
是否可以使用Spring RestTemplate而不使用Exceptions来处理状态为500的http响应?
RestTemplate restTemplate = new RestTemplate();
try {
response = restTemplate.getForEntity(probe.getUrl(), String.class);
boolean isOK = response.getStatusCode() == HttpStatus.OK;
// would be nice if 500 would also stay here
}
catch (HttpServerErrorException exc) {
// but seems only possible to handle here...
}
最佳答案
如果使用springmvc,则可以使用注释@ControllerAdvice创建控制器.在控制器中写:
@ExceptionHandler(HttpClientErrorException.class)
public String handleXXException(HttpClientErrorException e) {
log.error("log HttpClientErrorException: ", e);
return "HttpClientErrorException_message";
}
@ExceptionHandler(HttpServerErrorException.class)
public String handleXXException(HttpServerErrorException e) {
log.error("log HttpServerErrorException: ", e);
return "HttpServerErrorException_message";
}
...
// catch unknown error
@ExceptionHandler(Exception.class)
public String handleException(Exception e) {
log.error("log unknown error", e);
return "unknown_error_message";
}
并且DefaultResponseErrorHandler抛出这两种异常:
@Override
public void handleError(ClientHttpResponse response) throws IOException {
HttpStatus statusCode = getHttpStatusCode(response);
switch (statusCode.series()) {
case CLIENT_ERROR:
throw new HttpClientErrorException(statusCode, response.getStatusText(),
response.getHeaders(), getResponseBody(response), getCharset(response));
case SERVER_ERROR:
throw new HttpServerErrorException(statusCode, response.getStatusText(),
response.getHeaders(), getResponseBody(response), getCharset(response));
default:
throw new RestClientException("Unknown status code [" + statusCode + "]");
}
}
你可以使用:e.getResponseBodyAsString();, e.getStatusCode();控制器中的blabla建议在发生异常时获取响应消息.
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转载注明原文:如果Http状态为500,则Spring RestTemplate将始终抛出异常 - 乐贴网